Physics · 11 / 12

Radioactive decay: halve each half-life

Final-year concepts · Worked example and 4 exercises with solutions, at your pace.

The principle, simply

Individual decay is random. An exponential model predicts the average remaining in a large population of identical nuclei. Each half-life halves the previous population, not the initial one. Activity counts decays per second in becquerels.

n=1000*(1/2)^(t/5)
THE PICTURE TO REMEMBERRadioactive decay: halve each half-life
  1. 01Initial population
  2. 02Time / half-life
  3. 03Repeated factor 1/2
  4. 04Expected remainder

WORKED EXAMPLE

From principle to reasoning

For 1,000 nuclei and a half-life of 5 time units, expected counts are 500 at t = 5, 250 at t = 10 and 125 at t = 15. Plot 1000 × (1/2)^(x/5), with x representing time.

Solve a problem in this subject

  1. Draw the system

    Define the studied object, reference frame and positive axis. A force diagram shows external interactions acting on the system.

  2. Sort quantities

    Separate data and unknowns; convert units before substitution. 36 km/h = 10 m/s, so never insert 36 into a formula expecting SI speed.

  3. Write the model

    Choose a law matching assumptions: constant acceleration, thin lens, ohmic resistor. Isolate the unknown symbolically before rounding.

  4. Interpret

    Check dimensions and signs. Negative velocity gives direction on the chosen axis. Discuss scale and model limitations.

YOUR TURN

01 · Try before checking

What fraction remains after four half-lives?

One hint

Multiply by 1/2 four times.

Reveal and understand the solution

(1/2)⁴ = 1/16 = 6.25%. It does not predict when an individual nucleus decays.

Compare method, conditions and answer; identify the exact part to revisit.

IMPROVE THROUGH PRACTICE

Three additional challenges with solutions

Start with the first challenge. Write your method before opening a hint; use the solution to find the first step that needs work.

Reflect after practising
02 · Recognise and understandLink to this exercise

Start with 800 nuclei. After two half-lives, how many remain on average?

A hint to get started

Each half-life halves the amount.

Step-by-step solution
  1. After one half-life: 400.
  2. After two: 200.
  3. This is a model average; individual decays are random.

Which step did you miss? Retry without help, then explain why the method works.

03 · Apply the methodLink to this exercise

For N(t) = N₀e^(−λt), relate λ and half-life T.

A hint to get started

Set N(T)/N₀ = 1/2.

Step-by-step solution
  1. e^(−λT) = 1/2.
  2. −λT = −ln(2).
  3. T = ln(2)/λ; λ has inverse-time units.

Which step did you miss? Retry without help, then explain why the method works.

04 · Go furtherLink to this exercise

An isotope has a 4 h half-life. When does it reach 1/8 of its initial amount?

A hint to get started

Express 1/8 as a power of 1/2.

Step-by-step solution
  1. 1/8 = (1/2)³.
  2. Three half-lives are required.
  3. Time: 3 × 4 = 12 h.

Which step did you miss? Retry without help, then explain why the method works.

The trap to avoid

A half-life is not the time until all nuclei disappear.

Without notes, can you…

  • Explain the principle in your own words?
  • Rebuild the diagram and its connections?
  • Solve the exercise and justify the method?

Choosing a state saves it in this browser. This is your assessment, not a grade.